a^4+a^2b^2+b^4=

Simple and best practice solution for a^4+a^2b^2+b^4= equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for a^4+a^2b^2+b^4= equation:


Simplifying
a4 + a2b2 + b4 = 0

Reorder the terms:
a2b2 + a4 + b4 = 0

Solving
a2b2 + a4 + b4 = 0

Solving for variable 'a'.

Begin completing the square.

Move the constant term to the right:

Add '-1b4' to each side of the equation.
a2b2 + a4 + b4 + -1b4 = 0 + -1b4

Combine like terms: b4 + -1b4 = 0
a2b2 + a4 + 0 = 0 + -1b4
a2b2 + a4 = 0 + -1b4
Remove the zero:
a2b2 + a4 = -1b4

The a term is a2b2.  Take half its coefficient (0.5b2).
Square it (0.25b4) and add it to both sides.

Add '0.25b4' to each side of the equation.
a2b2 + a4 + 0.25b4 = -1b4 + 0.25b4

Combine like terms: -1b4 + 0.25b4 = -0.75b4
a2b2 + a4 + 0.25b4 = -0.75b4

Factor a perfect square on the left side:
(a2 + 0.5b2)(a2 + 0.5b2) = -0.75b4

Can't calculate square root of the right side.

The solution to this equation could not be determined.

See similar equations:

| f(x)=2x+z^2+3(4x)+17 | | m=-2+1p | | x^2+xy+y^2=2 | | 2x+10=x+25+10 | | -(x+5)=2x+16 | | 2x=x+25+10 | | x^2+xy+y^2-2=0 | | x^2+mx+m^2-2=0 | | 4-8/5*7/2*2/3*5/4= | | 1/20-8/5= | | 20/1-8/5= | | 4-8/5= | | hunor+borcsa=csaken | | xuygbn+uihnmb-yujnva=poiuytr | | m+n+m=20 | | sin(9x+7)+cos(11x+1)=0 | | X^2+2x+5=48 | | y=19lnx | | 35=20+15logx | | y=19ln(x)+12 | | -2(x-5)=28 | | 20-2(3x+8)=8-5x | | 7(5x-4)=77 | | -1+30x+24=6(5x+4) | | 2x+3(x-1)=68x-39+13 | | -7+5x=4+2x | | 4-2x-30y+15xy= | | 2x^2+3x-a=0 | | 5m+zr=r-8f | | h(x)=0.4x+2 | | v=0.8 | | 30=5x*10 |

Equations solver categories